Site navigation

\(\begin{array}{|c|c|c|} \hline \textbf{List I} & \textbf{List II} \\ \hline \text{A. Mean of first five prime numbers is} & \text{I. 12} \\ \hline \text{B. Mean of all factors of 24 is} & \text{II.…

Question and options

List IList IIA. Mean of first five prime numbers isI. 12B. Mean of all factors of 24 isII. 7.5C. Mean of first six multiples of 4 isIII. 5.6D. If the mean of x−5y,x−3y,x−y,x+y,x+3y and x+5y is 12, then x isIV. 14\begin{array}{|c|c|c|} \hline \textbf{List I} & \textbf{List II} \\ \hline \text{A. Mean of first five prime numbers is} & \text{I. 12} \\ \hline \text{B. Mean of all factors of 24 is} & \text{II. 7.5} \\ \hline \text{C. Mean of first six multiples of 4 is} & \text{III. 5.6} \\ \hline \text{D. If the mean of } x - 5y, x - 3y, x - y, \\x + y, x + 3y \text{ and } x + 5y \text{ is 12, then } x \text{ is} & \text{IV. 14} \\ \hline \end{array}

Match List I with List II. Choose the correct answer from the given options:
  1. A-II, B-I, C-III, D-IV
  2. A-III, B-II, C-IV, D-I
  3. A-I, B-IV, C-II, D-III
  4. A-IV, B-III, C-I, D-II

Answer and explanation

Correct answer: B - A-III, B-II, C-IV, D-I
A: (2+3+5+7+11)/5 = 5.6 -> III. B: factors of 24 sum to 60, 60/8 = 7.5 -> II. C: (4+8+...+24)/6 = 84/6 = 14 -> IV. D: the y terms cancel, so the mean = x = 12 -> I.

Practice for these exams

  • JIPMAT

Related question papers

Related exam syllabi

More solved explanations in Arithmetic