An XPS electron of an element was found to have a K.E. of 1052.6 eV when ejected with an Al $\mathrm{K\alpha}$ source (1486.6 eV) with work function 27.8 eV. What will be the B.E. energy of…

Question

An XPS electron of an element was found to have a K.E. of 1052.6 eV when ejected with an Al $\mathrm{K\alpha}$ source (1486.6 eV) with work function 27.8 eV. What will be the B.E. energy of electrons?

Accepted Answer

C - 406.2 eV. Binding energy = $h\nu - \mathrm{KE} - \phi = 1486.6 - 1052.6 - 27.8 = 406.2\ \mathrm{eV}$, where $\phi$ is the work function.

Answer

A - 829.5 eV

Answer

B - 434 eV

Answer

D - 510.2 eV

An XPS electron of an element was found to have a K.E. of 1052.6 eV when ejected with an Al \(\mathrm{K\alpha}\) source (1486.6 eV) with work function 27.8 eV. What will be the B.E. energy of…

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