An alloy \(P\) has copper and zinc in the proportion of \(5:2\) (by weight), while another alloy \(Q\) has the same metals in the proportion of \(3:4\) (by weight). If these two alloys are mixed in…
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An alloy has copper and zinc in the proportion of (by weight), while another alloy has the same metals in the proportion of (by weight). If these two alloys are mixed in the proportion of (by weight), a new alloy is formed, which has equal contents of copper and zinc. Then, the proportion of copper and zinc in the alloy , formed by mixing the two alloys and in the proportion of (by weight) is
Answer and explanation
Correct answer: C - \(9:5\)
Copper fractions 5/7 and 3/7: (5a+3b)/(7(a+b)) = 1/2 gives b = 3a. Mixing b:a = 3:1: copper = (15+3)/28 = 18/28, zinc 10/28, ratio 9:5.
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