A train left point A at 12 noon. Two hours later, another train started from point A in the same direction. It overtook the first train at 8 PM. It is known that the sum of the speeds of the two…
Question and options
A train left point A at 12 noon. Two hours later, another train started from point A in the same direction. It overtook the first train at 8 PM. It is known that the sum of the speeds of the two trains is 140 km/hr. Then, at what time would the second train overtake the first train, if instead the second train had started from point A in the same direction 5 hours after the first train? Assume that both the trains travel at constant speeds.
- 3 AM the next day
- 4 AM the next day
- 8 AM the next day
- 11 PM the same day
Answer and explanation
Correct answer: C - 8 AM the next day
First train runs 8 h, second 6 h to meet: 8v1=6v2, v2=4v1/3; v1+v2=140 -> v1=60, v2=80. With a 5 h gap, lead = 300 km, closing speed 20 km/h -> 15 h after 5 PM = 8 AM next day.
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IPMAT Indore
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