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A tin contains 50 paise, 25 paise and 10 paise coins in the ratio 5 : 9 : 4, amounting to Rs. 206. Find…

Let the numbers of 50 paise, 25 paise and 10 paise coins be \(5x,9x,4x\). Their total value in rupees is \(2.5x+2.25x+0.4x\) \(=5.15x\) \(=206\), so \(x=40\). The respective…

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A tin contains 50 paise, 25 paise and 10 paise coins in the ratio 5 : 9 : 4, amounting to Rs. 206. Find the number of coins of each type respectively.

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Let the numbers of 50 paise, 25 paise and 10 paise coins be 5x,9x,4x5x,9x,4x. Their total value in rupees is 2.5x+2.25x+0.4x2.5x+2.25x+0.4x =5.15x=5.15x =206=206, so x=40x=40. The respective numbers of coins are therefore 200, 360 and 160.

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