A student walks from his house at speed of \(2\frac{1}{2}\) km/hour and reaches his school late by 6 min. Next day, he increases his speed by 1 km/hour and reaches 6 min before school time. How far…
Question and options
A student walks from his house at speed of km/hour and reaches his school late by 6 min. Next day, he increases his speed by 1 km/hour and reaches 6 min before school time. How far is the school from his house?
- km
- km
- km
- km
Answer and explanation
Correct answer: B - \(\dfrac{7}{4}\) km
Time difference = 12 min = 1/5 h. d/2.5 - d/3.5 = d(2/5 - 2/7) = 4d/35 = 1/5, so d = 7/4 km.
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