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A person travelled a distance of 610 km in 9 hours. He travelled the first phase at a speed of 40 kmph…

Let the first part be \( x \) km. Then \( \tfrac{x}{40} + \tfrac{610 - x}{90} = 9 \); multiplying by 360 gives \( 9x + 2440 - 4x = 3240 \), so \( 5x = 800 \) and \( x = 160…

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A person travelled a distance of 610 km in 9 hours. He travelled the first phase at a speed of 40 kmph and the rest at 90 kmph. The distance travelled during the first phase is

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Correct answer C

Let the first part be x x km. Then x40+610−x90=9 \tfrac{x}{40} + \tfrac{610 - x}{90} = 9 ; multiplying by 360 gives 9x+2440−4x=3240 9x + 2440 - 4x = 3240 , so 5x=800 5x = 800 and x=160 x = 160 .

Check: 160 km at 40 kmph takes 4 hours and 450 km at 90 kmph takes 5 hours, 9 hours in all.

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