A new sequence is obtained from the sequence of positive integers \((1,2,3, \ldots)\) by deleting all the perfect squares. Then the \(2022^{\text {nd }}\) term of the new sequence is

The term is $2067$. Exactly $45$ positive squares are at most $2067$, since $45^2=2025$ and $46^2=2116$, leaving $2067-45=2022$ surviving terms and $2067$ itself among them. Adding just $44$, as in $2066$, overlooks $45^2$, which occurs before that value.