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A natural number \(n\) lies between \(100\) and \(400\), and the sum of its digits is \(10\). The probability that \(n\) is divisible by \(4\), is

Question and options

A natural number nn lies between 100100 and 400400, and the sum of its digits is 1010. The probability that nn is divisible by 44, is
  1. 14\frac{1}{4}
  2. 727\frac{7}{27}
  3. 13\frac{1}{3}
  4. 29\frac{2}{9}

Answer and explanation

Correct answer: B - \(\frac{7}{27}\)
Digit sum 10: hundreds digit 1 gives 10 numbers, 2 gives 9, 3 gives 8, total 27. Divisible by 4: 136, 172, 208, 244, 280, 316, 352, which is 7. Probability = 7/27.

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