A jewel thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 m ahead of the policeman, then the time required for the policeman to catch the thief will be
Question and options
A jewel thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 m ahead of the policeman, then the time required for the policeman to catch the thief will be
- 2 min
- 3 min
- 4 min
- 6 min
Answer and explanation
Correct answer: B - 3 min
Relative speed = 10 - 8 = 2 km/h. Time to close 100 m = h = h = 3 minutes.
Practice for these exams
-
CUSAT CAT Five-Year LL.B.
Related question papers
Related exam syllabi
More solved explanations in Arithmetic
- In a tournament 14 teams play league matches. If each team plays against every other team only once, then how many matches are played?
- A fair die is rolled repeatedly. The probability that the cumulative sum is at least 17 in the third trial is
- A merchant commences with a certain capital and gains annually at rate of 25%. At the end of 3 years his capital is worth Rs. 10000. What was his original capital ?
- The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is
- A car driver increases the average speed of his car by 3 km/hr every hour. The total distance travelled in 7 hours if the distance covered in first hour was 30 km,…