A fruit seller had a certain number of apples, bananas, and oranges at the start of the day. The number of bananas was 10 more than the number of apples, and the total number of bananas and apples…
Question and options
A fruit seller had a certain number of apples, bananas, and oranges at the start of the day. The number of bananas was 10 more than the number of apples, and the total number of bananas and apples was a multiple of 11. She was able to sell 70% of the apples, 60% of bananas, and 50% of oranges during the day. If she was able to sell 55% of the fruits she had at the start of the day, then the minimum number of oranges she had at the start of the day was
- 190
- 210
- 180
- 220
Answer and explanation
Correct answer: B - 210
Apples a, bananas a+10, oranges O. 0.7a+0.6(a+10)+0.5O=0.55(2a+10+O) gives O=4a+10. 2a+10 must be a multiple of 11 (a = 6 mod 11), and sold counts must be integers (0.7a integer so a multiple of 10). Smallest a=50, O=210.
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