Site navigation

A cylindrical vessel of base radius 42 cm contains water to a certain level. A solid cylinder of height 18 cm is dropped into it and is completely submerged in water. If the level of the water in…

Question and options

A cylindrical vessel of base radius 42 cm contains water to a certain level. A solid cylinder of height 18 cm is dropped into it and is completely submerged in water. If the level of the water in the vessel rises by 8 cm, what is the total surface area (in cm²) of the solid cylinder? (Use π=227 \pi = \frac{22}{7} ) (Assuming no overflow.)
  1. 6570
  2. 8096
  3. 7568
  4. 7040

Answer and explanation

Correct answer: B - 8096
Volume displaced: pi x 42^2 x 8 = pi x r^2 x 18, so r^2 = 784 and r = 28. TSA = 2 pi r (r + h) = 2 x (22/7) x 28 x 46 = 8096 cm^2.

Practice for these exams

  • IIM Bangalore BBA DBE Entrance Test

Related question papers

Related exam syllabi

More solved explanations in Arithmetic