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A and B take part in a rifle shooting match. The probability of A hitting the target is 0.4, while the probability of B hitting the target is 0.6. If A has the first shot, post which both strike…

Question and options

A and B take part in a rifle shooting match. The probability of A hitting the target is 0.4, while the probability of B hitting the target is 0.6. If A has the first shot, post which both strike alternately, then the probability that A hits the target before B hits it is
  1. 12\frac{1}{2}
  2. 1019\frac{10}{19}
  3. 23\frac{2}{3}
  4. 919\frac{9}{19}

Answer and explanation

Correct answer: B - \(\frac{10}{19}\)
A wins on the 1st, 3rd, ... shot: 0.4 * sum of (0.6*0.4)^n = 0.4/(1-0.24) = 0.4/0.76 = 10/19.

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  • IPMAT Indore

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